GMAT Quantitative Reasoning
and Data Insights Course

Let the fixed meter charge be X and the charge per unit be Y.

Thus, Electricity bill = X + kY, where k is the total number of units consumed.

Statement I:

Here, 2300 = X + 100Y

Since we do not have any information on the values of X and Y, this statement alone is not sufficient to answer the question.

Statement II:

Here, the charge per unit is 0.8Y.

Also, 2140 = X + 100*0.8Y

=> 2140 = X + 80Y.

Again, this statement alone is not sufficient alone to answer the question.

After combining both statements, we have,

2300 = X + 100Y....(i)

2140 = X + 80Y......(ii)

After subtraction (ii) from (i),

160 = 20Y

Thus, Y = 8

And, 2300 = X + 100*8

2300 - 800 = X

Thus, X = 1500

The electricity bill when Anuj consumed 75 units = 1500 + 75*8

=> 1500 + 600 = 2100

The correct option is C.

In this question, there are three possible cases:

i) Both glasses will break

ii) None of the glasses will break

iii) Any one glass will break

Thus, P(both glasses) + P(exactly one glass) + P(none glasses) = 1

It is given that the probability of exactly one glass breaking = 40% = 0.4

Statement I: Given that probability of both glasses surviving = 30% - 0.3

Now, P(both glasses) + P(exactly one glass) + P(none glasses) = 1

=> P(both glasses) + 0.4 + 0.3 = 1

=> P(both glasses) = 0.3

Thus, this statement is sufficient alone to answer the question.

Statement II: Since we can conclude this information even without using this statement, this statement alone is not sufficient to answer the question.

The correct option is A.

$$2^ab=48$$

or, $$2^ab=2^4\times3$$

So possible solutions are a

a=0, b=48

a=2, b=24

a=4, b=12

a=8, b=6

a=16, b=3

So we can see that even after using both the statements we cannot get a unique answer.

[Yes] According to the figure in NGO Report #1, the retail philanthropy segment constituted $80 billion [~33.33%] of the total funding in 2019, while the projected contribution for 2022 was $92 billion [~33.4%]. This shows an increase in the contribution from the retail segment.

[No] The combined social sector funding from retail [$80 Bn] and foreign philanthropists [$32 Bn] in Canada for the fiscal year 2019 was less than $120 billion [$112 Bn].

[No] The environment sector is projected to have a 40% (not 30%) growth in funding from 2020 to 2022.

[No] According to the figure in NGO Report #1, the social sector funding from foreign philanthropists in 2019 was $32 Bn, and the projected funding for 2022 was $28.8, indicating a decrease in funding.

[No] According to the figure in NGO Report #1, the projected growth in social sector funding for retail philanthropists is 15%, while for CSR funding, the projected growth is 25%.

[Yes] According to the figure in NGO Report #1, the social sector funding for HNIs in 2019 was $42 Bn, and the projected funding for 2022 is $50.4 Bn, indicating a growth of $8.4 Bn. On the other hand, the social sector funding for UHNIs in 2019 was $22 Bn, and the projected funding for 2022 is $24.2 Bn, indicating a growth of $2.2 Bn. Therefore, the growth in social sector funding for HNIs is higher than the growth for UHNIs.

2019:
social sector funding demand = $298 billion
actual funding = $240 billion.
deficit =$58 billion

2020:
a projected increase of $20 billion in social sector funding
actual funding = $240 billion + $20 billion = $260 billion
deficit = $110 billion
Estimated funding demand = deficit + actual funding = $260 billion + $110 billion = $370 billion

1. The revenue generated from region A = $26 million; the total revenue generated from all four regions = $100 million. Therefore, the % contribution of the revenue generated from region A in total revenue generated by all four regions together is 26%.

2. The revenue generated from the sale of product Y = $20 million; the total revenue generated from all four regions = $100 million. Therefore, the % contribution of the revenue generated from the sale of product Y in the total revenue generated by all four regions together is 20%. 

1. The city with the 4th highest average salary is Chennai, and the city with the 4th highest unemployment rate is also Chennai (True)

2. The life expectancy of Kolkata is 76 years
The average life expectancy of the other nine cities combined = 72+74+75+73+71+70+69+67+68 = 639
=> 639/9 = 71
It is 5 years more than the average of other 9 countries. (False)

3. The city with the lowest average age is Hyderabad,
The city with the 4th highest average expense per month among the top 10 cities in India is Bangalore (False)

Let the number of new plants added to the Species X plant population annually be ‘x’
The increase in the population of plant Species X after 7 years = 7x
Species X plant population after 7 years = 520 + 7x

Let the number of new plants added to the Species Y plant population annually be ‘y’
The increase in the population of plant Species Y after 7 years = 7y
Species Y plant population after 7 years = 800 + 7y

We know:
520 + 7x = 800 + 7y
7x - 7y = (800 - 520)
7(x - y) = 280 or (x - y) = 40

The only values of (x,y) from the given that satisfy the above condition are x = 110 and y = 70

120m can be written as (2*2*2*3*5*m). 

To get the square of an integer, m has to be at least (2*3*5) = 30, such that 120m = 120*30 = 3600, which can be written as $$(60)^2$$

The correct option is E.

$$\frac{\left(P+36\right)}{P}=1\ +\frac{36}{P}$$

We are told that the above expression is an integer, so P must be factor of 36.

Therefore, possible values of P are 1, 2, 3, 4, 6, 9, 12, 18 and 36

Sum = 1+2+3+4+6+9+12+18+36 = 91

Let the cost price of each mango be $x. Therefore, the cost price of 8 mangoes is $8x, which equals the selling price of 6 mangoes.

Hence, the selling price of 6 mangoes is $8x, which implies the selling price of 1 mango is (8x/6) = $(4x/3)

Hence, the profit percentage is {(4x/3 -x)/x}*100% = 33.33% of the cost price.

The correct option is D

Let the Length of race be d 

Speed of A = 3 m/s and B started 15 seconds after A 

A must be ahead by 3*15 = 45 meters, when B started.

When C started, A will be ahead by 3*20 = 60 meters and B will be ahead by 6*5 = 30 meters 

Let t be the time taken by C to cover the d distance 

Speed of c = 9 = d/t       -Eqn 1

Speed of a = 3= (d-60)/(t+20)     -Eqn 2

Substituting value d from Eqn 1 in Eqn 2, we get -

3 =(9t-60)/t+20)

3t+60 = 9t-60

6t= 120 

t = 20 

d = 9t 

d = 180m

B had already covered a distance of 30 meters when C started.

Time taken by B = (180-30)/6 = 25 seconds 

Hence, B will finish 5 seconds after C

Let scores of ram be 16x, 23x, 18x, 19x, 20x, 21x, and 24x

Total score = 16x +23x + 18x + 19x + 20x + 21x + 24x = 141x 

This is 47% of the total marks 

maximum marks = (100/47)*141x = 300x

maximum marks per test = 300x/7

42% marks per test = (42/100)*300x/7 = 18x

Hence we can conclude that he scored more than 42% marks in 5 tests- 19x, 20x, 21x, 23x, and 24x

We are replacing 12 litres of the 60 litres water solution with wine.

We are replacing 1/5th of the water solution with wine every replacement.

Hence water will reduce by 1/5th and remain 4/5th after every replacement.

We can say that after n replacements 

Quantity of water = $$60\times\left(\frac{4}{5}\right)^n$$

Quantity of water should be less than 35%

Quantity of water should be less than $$\frac{35}{100}\times60\ =21$$

$$60\times\left(\frac{4}{5}\right)^n$$ $$<21$$

$$\left(\frac{4}{5}\right)^n<\frac{21}{60}$$

$$\left(\frac{4}{5}\right)^n<\frac{7}{20}$$

min. n = 5

Let a, b and m be the prices of each apple, banana and mango, respectively.

Writing the given data in the form of equations, we get

4a + 3b + 10m = 96 and 2a + 6b + 7m = 95

We need to find the value of 10a + 3b + 23m, for which we need to write this expression as a linear combination of the given equations.

10a + 3b + 23m = x(4a+3b+10m) + y(2a+6b+7m)

Equating the coefficients of a and b, we get 10 = 4x + 2y and 3 = 3x + 6y

Multiplying the equation 4x + 2y = 10 with 3 and subtracting 3x + 6y = 3 we get,

12x + 6y - 3x - 6y = 30 - 3 => 9x = 27 => x = 3; substituting this in any of the above two equations, we get y = -1.

Therefore, 10a + 3b + 23m = 3(4a + 3b + 10m) -1(2a + 6b + 7m) = 3(96)-95 = 193.

We have five different observations.

In order to have the lowest value be as large as possible, we need the other values to be as low as possible.

Since 25 is the median, it will be the middle term of the five terms when arranged in ascending order.

We are given that the median is 25, so our numbers are _, _, 25, _, _.

Inserting the lowest available values for the top two gives us _, _, 25, 26, 27.

Let the lowest number be x and the second lowest number be x+1.
x + (x+1) + 25 + 26 + 27 = 5*19
2x + 79 = 95
2x = 16
x = 8

The probability of a surprise test each day is $$\frac{1}{2}$$, and the probability of no surprise test is also $$\frac{1}{2}$$.

The number of ways to select on which $$2$$ days out of $$6$$, there will be a surprise test is $$^6C_2=15$$

Hence, the probability that the surprise test is on exactly 2 days in a 6-day period is

$$^6C_2\times\ \left(\frac{1}{2}\right)^{^{6-2}}\times\ \left(\frac{1}{2}\right)^{^2}$$

$$=15\times\ \left(\frac{1}{2}\right)^{^6}\ =\ \frac{15}{64}$$

The correct option is D

For 6 to be the largest value among four cards, the other three cards must be from (1 to 5).

The number of ways to select these three cards is $$^5C_3$$.

The number of ways to choose four cards among nine cards is $$^9C_4$$.

Hence, the probability of getting six as the largest value = $$\ \frac{\ ^5C_3}{^9C_4}=\frac{10}{126}=\frac{5}{63}$$

The correct option is D